leetcode 461. Hamming Distance

Question

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Example

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Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.

Tip

位运算问题,对输入的两个数字做按位异或^操作,然后再利用位运算符>>计算结果中有多少个数字1出现

Code

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class Solution {
public:
int hammingDistance(int x, int y) {
int z = x ^ y;
int result = 0;
for(int i = 0; i < 32; i++) {
result += 1 & (z >> i);
}
return result;
}
};