Question
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Example
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| Input: x = 1, y = 4 Output: 2 Explanation: 1 (0 0 0 1) 4 (0 1 0 0) ↑ ↑ The above arrows point to positions where the corresponding bits are different.
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Tip
位运算问题,对输入的两个数字做按位异或^操作,然后再利用位运算符>>计算结果中有多少个数字1出现
Code
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| class Solution { public: int hammingDistance(int x, int y) { int z = x ^ y; int result = 0; for(int i = 0; i < 32; i++) { result += 1 & (z >> i); } return result; } };
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