leetcode 367. Valid Perfect Square

Question

Given a positive integer num, write a function which returns True if num is a perfect square else False.

Note: Do not use any built-in library function such as sqrt.

Example

Example 1:

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Input: 16
Returns: True
Example 2:
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Input: 14
Returns: False

Tip

判断输入数字是否是完全平方数

不停的对数字进行除以2的处理,判断结果的平方与输入数字的大小,如果大,继续除以2,否则,就在当前数和上次的数之间寻找是否有平方恰好等于输入数的。

Code

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class Solution {
public:
bool isPerfectSquare(int num) {
if (num == 1) return true;
long x = num / 2, t = x * x;
while (t > num) {
x /= 2;
t = x * x;
}
for (int i = x; i <= 2 * x; ++i) {
if (i * i == num) return true;
}
return false;
}
};